sqrt(5)sqrt(7)

<-- Enter expression

Evaluate √57

Term 1 has a square root, so we evaluate and simplify:
sqtot = 2
We have a product of 2 square root terms
The product of square roots is equal to the square root of the products
57 = √5*7
57 = √35
Simplify √35.

Checking square roots, we see that 52 = 25 and 62 = 36.
Our answer in decimal format is between 5 and 6
Our answer is not an integer, so we try simplify it into the product of an integer and a radical.

We do this by listing each product combo of 35 checking for integer square root values below:
35 = √135
35 = √57

From that list, the highest factor that has an integer square root is 1.
Therefore, we use the product combo √35 = √135
Evaluating square roots, we see that √1 = 1

Since 1 is the greatest common factor, this square root cannot be simplified any further:
Multiply by our constant of 1
35 = 35

Group square root terms for 1
1√35


Build final answer:
1√35