Evaluate √5√7

sqtot = 2

We have a product of 2 square root terms

The product of square roots is equal to the square root of the products

√5√7 = √5*7

√5√7 = √35

Simplify √35.

Checking square roots, we see that 5

Our answer in decimal format is between 5 and 6

Our answer is not an integer, so we try simplify it into the product of an integer and a radical.

√35 = √1√35

√35 = √5√7

From that list, the highest factor that has an integer square root is 1.

Therefore, we use the product combo √35 = √1√35

Evaluating square roots, we see that √1 = 1

Since 1 is the greatest common factor, this square root cannot be simplified any further:

√35 =

1√35