Term 1 has a square root, so we evaluate and simplify: sqtot = 2 We have a product of 2 square root terms The product of square roots is equal to the square root of the products √5√7 = √5*7 √5√7 = √35 Simplify √35.
Checking square roots, we see that 52 = 25 and 62 = 36. Our answer in decimal format is between 5 and 6 Our answer is not an integer, so we try simplify it into the product of an integer and a radical.
We do this by listing each product combo of 35 checking for integer square root values below: √35 = √1√35 √35 = √5√7
From that list, the highest factor that has an integer square root is 1. Therefore, we use the product combo √35 = √1√35 Evaluating square roots, we see that √1 = 1
Since 1 is the greatest common factor, this square root cannot be simplified any further: Multiply by our constant of 1 √35 = √35