z varies jointly with y and x, and z = 192 when x = 2 and y = - 6, solve for z when b = 2,c = 3

The statement denotes a relationship of z = kyx where k is a constant

Plugging in our initial statement values of z = 192 when x = 2 and y = - 6, we get:

192 = (2)(-6)k

192 = -12k

192 | |

-12 |

= |

-12k |

-12 |

k = -16

Because we have found our relationship constant k = -16, we form our new variation equation:

z = -16yx

Since we were given that b = 2,c = 3, we have

z = -16 x 2 x 3

z =