Show the divisibility for 64 in terms of 2,3,4,5,6,7,8,9,10,11

A number is divisible by 2 if the last digit ends in 0,2,4,6,8The last digit of 64 is 4

Since 4 is equal to 0,2,4,6,8, then 64 is divisible by 2

A number is divisible by 3 if the sum of it's digits ends is divisible by 3The sum of the digits for 64 is 6 + 4 = 10

Since 10 is

A number is divisible by 4 if the last two digits are divisible by 4The last 2 digits of 64 are 64

Since 64 is divisible by 4, then 64 is divisible by 4

A number is divisible by 5 if it ends with a 0 or 5The last digit of 64 is 4

Since 4 is

A number is divisible by 6 if it is divisible by both 2 and 3Since 64 is

To see if 64 is divisible by 7, we multiply each respective digit by 1,3,2,6,4,5 working backwards and repeat as necessary4(1) + 6(3) = 23

Since 23 is

A number is divisible by 8 if the last three digits are divisible by 8The last 2 digits of 64 are 64

Since 64 is divisible by 8, then 64 is divisible by 8

A number is divisible by 9 if the sum of it's digits is divisible by 9.The sum of the digits for 64 is 6 + 4 = 10

Since 10 is

A number is divisible by 10 if it ends with a 0The last digit of 64 is 4

Since 4 is

A number is divisible by 11 if the sum of the odd digits - the sum of the even digits = 0 or is a multiple of 11

64

6

Odd Sum = 6

64

4

Even Sum = 4

Δ = Odd Sum - Even Sum

Δ = 6 - 4

Δ = 2

Because Δ / 11 is not an integer = 5.8, then 64 is NOT divisible by 11

In summary, 64 is divisible by (