You start with an initial value of 1 which accumulates to 2 at a rate of 1.26480934686 exponentially. How long did this take?:

Since r = 1.26480934686 is greater than zero, we have an exponential growth equation

Pe

and t is time it takes to grow your initial investment/amount to A, your final value. Note: e is Eulers Constant = 2.

1e

1e^{1.26480934686t} | |

1 |

= |

2 |

1 |

e

Ln(e

There exists a logarithmic identity which states: Ln(e

1.26480934686t = 0.95

1.26480934686t | |

1.26480934686 |

= |

0.95 |

1.26480934686 |

t =

Therefore, it would take 0.34 units of time to increase an initial value of 1 to 2 at a rate of 1.26480934686 exponentially!