We need two consecutive integers (n) and (n + 1) who have a product = 72

Multiplying through, we get nWe need to find two integers, n and n + 1 who have a product of 72

n * (n + 1) = 72

Rearranging the equation we get n

a = 1, b = 1, and c = -72

Solution 1 = ½(-b + √b

Solution 1 = ½(-1 + √1

Solution 1 = ½(-1 + √1 - -288)

Solution 1 = ½(-1 + √289)

Solution 1 = ½(-1 + 17)

Solution 1 = ½(16)

Solution 1 =

Solution 2 = Solution 1 + 1

Solution 2 = 8 + 1

Solution 2 =

Also, since the product of 2 negative #'s is positive, another solution is:

Solution 3 = (-1 * 8) * (-1 * 9)

Solution 3 = -1 * 8

Solution 3 =

Solution 4 = -1 * 9

Solution 4 =

Since 8 * 9 = -8 * -9 = 72, we have our solutions.