Calculate the Z score using the Normal Approximation to the Binomial distribution given n = 10 and p = 0.4 with 3 successes with and without the Continuity Correction Factor

Z = | X - np |

√np(1 - p) |

μ = np

μ = 10 x 0.4

μ =

Since q = 1 - p, we have n(1 - p) = 10(1 - 0.4)

nq = 10(0.6)

nq = 6

Since np and nq are both not greater than 5, we